The sum of three numbers in A.P is 27 the product of first and last numbers is 65. Find the numbers
Answers
Answered by
1
Answer:
it is 9
Step-by-step explanation:
Let the three numbers in AP be a - d,a ,a + d
a - d + a + a + d=27
3a = 27
a = 9
If they would be a, a+d, a+2d then
a+a+d+a+2d = 27
a+d=9
d=0
tn = a + ( n - 1) d
= 9 +(n -1) 0
= 9
Answered by
0
Step-by-step explanation:
let the three numbers be a-d, a, a+d
Therefore, By 1st condition:
a-d+a+a+d=27
a+a+a=27
3a=27
a=27/3
a=9
by 2nd condition:
(a-d)×(a+d)=65
(a^2-d^2) =65
(9)^2 - d^2 = 65
81-d^2=65
81-65=d^2
d^2=16
d=√16
d=4
the 1st number= a-d = 9-4 =5
2nd number = a = 9
3rd number = a+d = 9 + 4 = 13
the no. s are 5,9,13
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