The sum of three numbers in A.P. is 3 and their product is -35. Find the number.
Answers
Answered by
5
Let the numbers are a-d, a and a+d sum 3a= 3
=> a=1
Product (a-d)a(a+d)= -35
=> d= +6 or -6
So the numbers are -5 , 1 and 7
Or 7,1 and -5
=> a=1
Product (a-d)a(a+d)= -35
=> d= +6 or -6
So the numbers are -5 , 1 and 7
Or 7,1 and -5
ak22nt:
To make our calculations simpler.
how??
explain plz??
You can take any other value as long as they are in ap.. But your calculations will be difficult
Ok
beacuse d and minus d cancel each other
Exactly
If you take a,a+d, and a+2d you will have to solve two equations to get a
it's quite confusing
Isn't it.
Answered by
12
let the numbers be
a-d,a,a+d
sum of terms= a-d+a+a+d=3
3a=3
a=1
AND
(a-d)(a)(a+d)= -35
a(a²-d²)=-35
putting value of a
1(1²-d²)=-35
1+35=d²
d=√36
d=6
So the numbers are : (1-6),1,(1+6)
-5,1,7
This is the correct answer for the given question.
AND IF YOU LIKE MY ANSWER DON'T FORGET TO HIT THE BRILLIANT BUTTON.
THANK YOU
a-d,a,a+d
sum of terms= a-d+a+a+d=3
3a=3
a=1
AND
(a-d)(a)(a+d)= -35
a(a²-d²)=-35
putting value of a
1(1²-d²)=-35
1+35=d²
d=√36
d=6
So the numbers are : (1-6),1,(1+6)
-5,1,7
This is the correct answer for the given question.
AND IF YOU LIKE MY ANSWER DON'T FORGET TO HIT THE BRILLIANT BUTTON.
THANK YOU
why a-d , a and a+d
beacuse we get only a while we add them
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