The sum of three numbers in A.P. is – 3, and their product is 8. Find the numbers.
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Solution :-
Let the number are x−y,x,x+y
Sum =−3
⇒x−y+3x+x+y=−3
⇒3x=−3
⇒x=−1
Now product =8
⇒(x−y)(x)(x+y)=8
Substituting x=−1
we get (−1−y)(−1)(−1+y)=8
(y
2
−1)=8
⇒y=±3
The no : are −4,−1,2 or 2,−1,−4
Step-by-step explanation:
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