The sum of three numbers in
a.p is 36 and sum of thier square is 450.find the numbers
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let three numbers be a-d;a;a+d
a-d+a+a+d=36
3a=36
a=12
sum of squares is 450
[a-d]²+[a]²+[a+d]²=450
simplify the sum you will get the answer substitute `a` place 12
a-d+a+a+d=36
3a=36
a=12
sum of squares is 450
[a-d]²+[a]²+[a+d]²=450
simplify the sum you will get the answer substitute `a` place 12
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