Question

The sum of three numbers in an AP is 24 and their product is 440. Find the numbers.

Answer 1

Answer:

THIS IS HOW YOU DO IT

Step-by-step explanation:

LET THE THREE NUMBERS BE (a-d),a,(a+d)

NOW THEIR SUM IS 24.HENCE,

(a-d)+a+(a+d)=24

3a=24

a=8

NOW,

THEIR PRODUCT IS 440

a(a-d)(a+d)=440

a(a^2-d^2)=440

a^3-ad^2=440

put value of a

512-8d^2=440

8d^2=512-440

8d^2=72

d^2=9

d=3 or d=-3

WHEN a=8 and d=3

numbers are 5,8,11

ALSO numbers will be again 5,8,11 when d=-3 and a=8

HENCE THE NUMBERS IN AP ARE 5,8,11

HOPW I HELPED YOU