the sum of three numbers in an AP is -3 and their product 8.find the numbers
Answers
Answered by
10
Let the nos be (a-d), a & (a+d)
(a-d) + a + (a+d) = -3
3a = -3
a= -1
(-1-d)*(-1)*(-1+d) = 8
-(d+1)* (-1)* (d-1) =8
(d+1)*(d-1) = 8
d^2-1 = 8
d^2 = 9
d = +3 or -3
with either value of d, the nos are
-4, -1, +2
(a-d) + a + (a+d) = -3
3a = -3
a= -1
(-1-d)*(-1)*(-1+d) = 8
-(d+1)* (-1)* (d-1) =8
(d+1)*(d-1) = 8
d^2-1 = 8
d^2 = 9
d = +3 or -3
with either value of d, the nos are
-4, -1, +2
Similar questions