The sum of three numbers in an AP is (-3), and their product is 8. Then numbers are
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5
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Step-by-step explanation:
Let the three numbers be a - d, a , a + d
a - d + a + a + d = - 3
3a = -3
a = -1
(a-d)(a)(a+d) = 8
a(a^2 - d^2) = 8
-1(1 - d^2) = 8
-1 + d^2 = 8
d^2 = 9
d = 3
a - d = - 4
a = - 1
a + d = 2
Answered by
7
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