The sum of three numbers in an ap is -3and their product is 8find the numbers
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the three numbers which when add gives -3 and when multipled gives 8 are -4, -1, 2
sanjanasanath44:
can i get the working
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since the sum of three no. in an ap is -3
therefore, three no. are (a-d), a, (a+d)______(1)
(a-d)+a+(a+d)= -3
a-d+a+a+d=-3
3a=3
therefore a=1
also. their product is 8
(a-d)(a)(a+d)=8
put a=1
(1-d)(1)(1+d)=8
1squre- d squre=8
d=+-√7
put values of a. &. d in eqn 1 and get ans...
therefore, three no. are (a-d), a, (a+d)______(1)
(a-d)+a+(a+d)= -3
a-d+a+a+d=-3
3a=3
therefore a=1
also. their product is 8
(a-d)(a)(a+d)=8
put a=1
(1-d)(1)(1+d)=8
1squre- d squre=8
d=+-√7
put values of a. &. d in eqn 1 and get ans...
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