The sum of three numbers in AP 27 and their product is 405. Find the numbers.
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Let the three numbers in A.P is a−d,a,a+d
Sum of three numbers is 27
⟹a−d+a+a+d=27⟹a=9
Product is 405
⟹(9−d)(9)(9+d)=405
⟹81−d
2
=45⟹d
2
=36⟹d=±6
The numbers are 3,9,15
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