Question

The sum of
three numbers in AP are 3
and their product is - 35.
Find the numbers​

Answer 1

From the question it is given that,

The sum of three numbers in A.P. =3

Given, Their product =−35

Let us assume the 3 numbers which are in A.P. are, a−d,a,a+d

Now adding 3 numbers =

a−d+a+a+d=3

3a=3

a=3/3

a=1

From the question, product of 3 numbers is - 35

So, (a−d)×(a)×(a+d)=−35

(1−d)×(1)×(1+d)=−35

1

2

−d

2

=−35

d

2

=35+1

d

2

=36

d=

3

6

d=±6

Therefore, the numbers are (a−d)=1−6=−5

a=1

(a+d)=1+6=7

The numbers are (a−d)=1−(−6)=1+6=7

a=1

(a+d)=1+(−6)=1−6=−5

Therefore, the numbers −5,1,7,… and 7,1,−5,… are in A.P.

Answer 2

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