the sum of three numbers in AP is 12 and the ratio of first number to third number is 1:3 find the numbers
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let k be the reqd ratio
a3 = 3k ; a = k
S3 = [ a + l ] n /2
=> 12 = (3k + k) . 3/2
=> 12*2/3 = 4k
=> 8 = 4k => k = 2
therefore, a = 2, a3 = 6
( here in ap a is first term and a3 is third term)
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