the sum of three numbers in AP is 12 and the sum of their cubes is288. find the numbers
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Answer:
a=4,d=+or-2
Step-by-step explanation:
the three numbers are a-d,a,a+d
a-d+a+a+d=12
3a=12
a=4
(a-d)cube+acube+(a+d)cube=288
a3-d3-3a2d+3ad2+a3+a3+3a2d+3ad2=288
3a3+6ad2=288
3(4)cube+6(4)d2=288
24d2=288-192
24d2=96
d2=96/24
d2=4
d=+or-2
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