the sum of three numbers in ap is 12 and the sum of there cube is 288 find the number
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hey mate!
let the three nos. be a-d, a+d
so, a-d+a+a+d=12
3a=12
a=12/3
a=4
(a-d)^3+a^3+(a+d)^2=288
now you can substitute the value of a in the equation and solve for d
hope it helps!!
let the three nos. be a-d, a+d
so, a-d+a+a+d=12
3a=12
a=12/3
a=4
(a-d)^3+a^3+(a+d)^2=288
now you can substitute the value of a in the equation and solve for d
hope it helps!!
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