the sum of three numbers in ap is 18 and there product is 182 find the number
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let three no. be a-d, a, a+d
according to first condition,
a-d+a+a+d = 18
3a = 18
a = 6......(1)
according to second condition,
(a-d) a (a+d) = 182
a ( a²-d²) = 182
6 ( 6² - d²) = 182
36 - d² = 3.3
-d² = 3.3 - 36
-d² = -32.7
d² = 32.7
d = 5.7 or d = -5.7
when d = 5.7 the three no. are
0.3, 6, 11.7
when d = -5.7 the three no. are
11.7, 6, 0.3
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