Question

the sum of three numbers in AP is 21 and product is 231.
find the numbers

Answer 1

Let the AP is (a-d), a, (a+d)  (a-d)+a+(a+d) =21 3a=21 a=7 (a-d)×a×(a+d)=231 (a×a-d×d) ×a=231 (7×7-d×d)×7=231 (7×7-d×d)=231÷7 (7×7-d×d)=33 d×d=49-33 d×d=16 d=4 Hence, the A. P. is 3, 7, 11.

Answer 2

Answer:

Step-by-step explanation:

Let the AP is (a-d), a, (a+d)

(a-d)+a+(a+d) =21

3a=21

a=7

(a-d)×a×(a+d)=231

(a×a-d×d) ×a=231

(7×7-d×d)×7=231

(7×7-d×d)=231÷7

(7×7-d×d)=33

d×d=49-33

d×d=16

d=4

Hence, the A. P. is 3, 7, 11.

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