the sum of three numbers in AP is 27 and their product is 405, find the numbers
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Let the three numbers in A.P is a−d,a,a+d
Sum of three numbers is 27⟹a−d+a+a+d=27⟹a=9
Product is 405⟹(9−d)(9)(9+d)=405⟹81−d 2 =45⟹d 2 =36⟹d=±6The numbers are 3,9,15
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