The sum of three numbers in G.P. is 70. If the two extremes by multiplied each by 4 and the mean by
5, the products are in AP. The numbers are
(a) 12, 18, 40
(b) 10, 20, 40
(c) 40, 20, 15
(d) none of these
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Answer:
Let a,ar,ar^2 be three terms of G.P.
Common ratio =r
Given :
a+ar+ar^2 =70 .......... (1)
Also, 4a,5ar,4ar^2 are in A.P.
∴4a+4ar^2 =2×5ar
⇒2+2r^2=5
⇒2r^2−5r+2=0
∴r=2, 1/2
Putting value of r=2 in eqn. (1), we get
a(1+2+4)=70
⇒a=10
Thus, the numbers are 10,20,40.
hope you understand
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