Question

the sum of three numbers is 109 the second number is four times the first number and the third number is 8 less than the second number find the three numbers ​

Answer 1

Answer:

Answer is below, Hope it helps.

Step-by-step explanation:

First number = x

Second number = 4x

Third number = 4x - 8

Sum of numbers = 109

x + 4x + 4x - 8 = 109

9x - 8 = 109

9x - 8 = 109

9x - 8 + 8 = 109 + 8

9x = 117

x = 117/9

x = 13

First number = x = 13

Second number = 4x = 4 x 13 = 52

Third number = 4x - 8 = 52 - 8 = 44