The sum of three numbers is 123. If the ratio between first and second number is 2:5 and that of between second and third is 3:4 then find the difference between second and third number.
Answers
Let the three numbers be a, b, and c.
Given that
a:b = 2:5
We can also write it as
a:b=6:15
Alos second given condition is
b:c = 3:4
We can also write it as
b:c = 15:20
Hence from above equations
a:b:c = 6:15:20
Let us assume that a = 6x, b = 15x and c = 20x
Given sum of all the three numbers = 123
On adding all the three numbers we get,
a+b+c =123
6x+15x+20x =123
41x = 123
x = 3
Hence a = 18, b = 45 and c = 60.
The difference between the second and the third number is 60 – 45 =15
Let the three numbers be a, b, and c.
Given that
a:b = 2:5
We can also write it as
a:b=6:15
Alos second given condition is
b:c = 3:4
We can also write it as
b:c = 15:20
Hence from above equations
a:b:c = 6:15:20
Let us assume that a = 6x, b = 15x and c = 20x
Given sum of all the three numbers = 123
On adding all the three numbers we get,
a+b+c =123
6x+15x+20x =123
41x = 123
x = 3
Hence a = 18, b = 45 and c = 60.
The difference between the second and the third number is 60 – 45 =15