Question

the sum of three numbers is 132. If the first number be twice the second and third number be one-third of the first, then the second number is:

Answer 1

Let first no. be x

second no. 2x

third no. =2x/3

sum of three is 132

x+2x+2x/3=132

3x+6x+2x/3=132
11x/3=132

11x=396
x=396/11

x=36


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Answer 2

Answer:

then the second number is: x=36

Step-by-step explanation:

As given withinside the query the 3 components are in AP then permit the 3 components of 24 is a−d,a,a+d. Then submission of all 3 components is identical to 24 from right here we are able to calculate a. then the manufactured from 3 components is 440 from this we are able to calculate d. So, 3 components of 24 are 5, 8, 11. Addition is an crucial idea of Mathematics. When we upload  or extra numbers, the end result or the solution we get may be described because the SUM. The numbers which might be introduced are known as addends. In the above example, 6 and four are addends, and 10 is their sum.

Let first no. be x

2d no. 2x

1/3 no. =2x/3

sum of 3 is 132

x+2x+2x/3=132

3x+6x+2x/3=132

11x/3=132

11x=396

x=396/11

x=36

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