Question

The sum of three numbers is 150. First number is rd of the second number. The second number is th of the third number. By how much is the first number less than the third number?​

Answer 1

Answer:

86

Step-by-step explanation:

Now, second number is thrice the first.

So, y = 3x

Third number is 10 less than twice the second.

So, z = 2y - 10

Now, sum of all three numbers is 150.

So,

x + y + z =150

x + 3x + (2y - 10) = 150

x + 3x + (2(3x) - 10) = 150

x + 3x + 6x - 10 = 150

10x - 10 = 150

10x = 160

x = 16

Now,

y = 3x = 3 × 16 = 48

z = 2y - 10 = 2(48) - 10 = 86

So, 16 + 48 + 86 = 150