Question

The sum of three numbers is 25. The second number is twice the first and third exceeds second by 5. Find the number​

Answer 1

Answer:

Your second number is twice the first, so it is 2x. 

Your third number exceeds the second number by 5, so it is 2x + 5. 

When you add these three numbers up, the sum is 25: 

x + 2x + (2x + 5) = 25 

Combine "like" terms: 

5x + 5 = 25 

Now, isolate (or solve for) x. First, subtract 5 from both sides of the equation: 

5x + 5 - 5 = 25 - 5 

5x = 20 

Then, divide both sides of the equation by 5: 

5x/5 = 20/5 

x = 4 

So our first number is 4. 

The second number is twice this, or 8. 

The third number exceeds 8 by 5. Since 8 + 5 = 13, 13 is our third number. 

Finally, 

4 + 8 + 13 = 25 

I hope this was helpful! :)