Question

The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.

Answer 1

Let no be = x

so 2nd no = 2×x = 2x

3rd no = x +6

sum = 26

x + 2x + x + 6 = 26

4x = 20 - 6

4x = 20

x = 20÷4

x = 5

therefore 2nd no 2×5 = 10

3rd no = 5+ 6 = 11

1st no 5

Answer 2

First no. = x

Second no. = 2x

Third no. = 2x + 6

x + 2x + 2x + 6 = 26

5x + 6 = 26

5x = 26 - 6

5x = 20

x = 20/5

x = 4

So, the first no. = 4

Second no. = 4 × 2 = 8

Third no. = 2 × 4 + 6 = 14

Hope it helps .

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