Question

The sum of three numbers is 48. The second number is three times the first, while the third number is twice the first.
Find the numbers
What is the average of the numbers

Answer 1

Answer:

ur answer is attached above

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Answer 2

${\huge{\overbrace{\underbrace{\blue{Given}}}}}}$

• Sum of three numbers = 48

• Second no = 3×First no

• Third no = 2×First no

${\huge{\overbrace{\underbrace{\blue{ToFind}}}}}}$

• The three numbers

• Average of three numbers

${\huge{\overbrace{\underbrace{\blue{Solution}}}}}}$

Let,

• 1st no be x

Then,

According to Question :-

• Second No = 3x

• Third no = 2x

So,

• => x + 3x + 2x = 48

• => 6x = 48

• => x = 48/6 =8

So,

• First no = x = 8

• Second Number = 3x = 3×8 = 24

• Third Number = 2x = 2 ×8 = 16

Now,

Average of Numbers -

$\frac{sum \: of \: quantity}{no \: of \: quantity} \\ = \frac{48}{3} = 16$