Question

the sum of three numbers is 57 .If twice the first number is6 less than the second and the second number is 10 more than the third , find the numbers​

Answer 1

Step-by-step explanation:

Consider the numbers x,y,z

X+y+z=57

2x=y-6

y=10+z

y=2x+6

z=y-10

=2x+6-10

z=2x-4

x+y+z=57

x+2x+6+2x-4=57

5x+2=57

5x=55

x=11

y=27

z=18

Answer 2

Answer:

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