Question

The sum of three numbers is 58. The second number is 3 times of 2/5 of the first number and the third number is 6 less than the first number. Find the three numbers.

Pls ans with explanation​

Answer 1

Answer:

First Number = 20

Second Number = 24

Third Number = 14

Step-by-step explanation:

Let the first number be 'x'

Let the second number be 'y'

Let the third number be 'z'

Since, second number = 3*2/5x

Therefore, y = 3*2/5x

Since, third number = x-6

Therefore, z = x-6

Since, x + y + z = 58

Therefore, x + (3*2/5x) + (x-6) = 58

x + (6/5x) + (x-6) = 58

x + (6/5x) + x = 58 + 6

(Making denominators same)

5x/5 + 6x/5 + 5x/5 = 64

16x/5 = 64

16x = 64*5

16x = 320

x = 320/16

Hence, x = 20

Therefore, First number = x = 20

Second number = (3*2/5) * 20 = 6/5*20 = 6*4 = 24

Third number = x-6 = 20-6 = 16

Hope you understand

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