Question

the sum of three numbers is 58. the second number is three times of two-fifth of the first number and the third number is 6 less than the first number . find the three numbers.​

Answer 1

Answer:

1. 20,24,14

Step-by-step explanation:

1. let the three numbers be x,x1,x2
2. as per given data

x1=x*2/5*3 and

1. x2=x-6

also as per given data

sum of three numbers=58

x+x1+x2=58

x+x*2/5*3+(x-6)=58

x+6x/5+x-6=58

5x+6x+5x-30=58*5

16x-30=290

16x=290+30

16x=320

x=320/16

x=20

so, x=20

x1=x*2/5*3

x1=20*2/5*3

x1=4*2*3

x1=24

x2=x-6

x2=20-6

x2=14