Question

the sum of three numbers is 66 . The second number is twice the first and six less than the third. Find the numbers

Answer 1

The numbers are 18, 36, 12.

Answer 2

Answer:

12, 24, 30

Step-by-step explanation:

Let the first number be N

Second number = 2N   [ Twice the first]

Second number(2N) is(=)  6 less(-6)  than the third

2N = Third Number - 6

Third number = 2N + 6

Now, Sum of these three numbers = 66

First Number + Second Number + Third Number = 66

N + 2N + 2N + 6 = 66

5N = 66 - 6

5N = 60

N = 60/5

N = 12

∴        First Number (N) = 12

  Second Number (2N) = 24

Third Number (2N + 6) = 30