Question

The sum of three numbers is 98. If the ratio between the first and second be 2:3 and that between the second and third be 5: 8, then find the second number.

Answer 1

Step-by-step explanation:

$let \: a \: is \: to \: b \: and \: b \: isto \: c$

then a:b = 2:3

and b: c=5:8

then a:b::b:c=2:3::5:8

a:c= 2:8

lcm of 3,5=15

$then \: \frac{2}{3} \times \frac{2 \times 5}{3 \times 5} = \frac{10}{15}$

$\frac{5}{8} \times \frac{5 \times 3}{8 \times 3 = 4990}$

Answer 2

Answer:

Step-by-step explanation:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.