The sum of three numbers is 98. If the ratio of the first tosecondis 2 :3 and that of the second to the third is 5 : 8, then the second number is:
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Let the three parts be A, B, C. Then,
A : B = 2 : 3 and B : C = 5 : 8 = 5 x 3/5 : 8 x 3/5 = 3 : 24/5
A : B : C = 2 : 3 : 24/5 = 10 : 15 : 24
B = (98 x 15/49) = 30.
A : B = 2 : 3 and B : C = 5 : 8 = 5 x 3/5 : 8 x 3/5 = 3 : 24/5
A : B : C = 2 : 3 : 24/5 = 10 : 15 : 24
B = (98 x 15/49) = 30.
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Answer:
Step-by-step explanation:
Solution:
Let the three numbers be x, y and z.
Sum of the numbers is 98.
x + y + z = 98………………(i)
The ratio of the first to the second is 2/3.
x/y = 2/3.
x = 2/3 × y.
x = 2y/3.
The ratio of the second to the third is 5/8.
y/z = 5/8.
z/y = 8/5.
z = 8/5 × y.
z = 8y/5.
Put the value of x = 2y/3 and z = 8y/5 in (i).
2y/3 + y + 8y/5 = 98
49y/15 = 98.
49y = 98 × 15.
49y = 1470.
y = 1470/49.
y = 30 .
Therefore, the second number is 30.
Answer: (c)
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