Math, asked by scorp9ocean, 1 year ago

The sum of three numbers is 98. If the ratio of the first to second is 2:3 and that of the second to the third is 5:8, then find the second number.

Answers

Answered by sneha73

the three no are 20 30 and 48

scorp9ocean: Can you post the solution?? please

sneha73: u may not understand

scorp9ocean: for only answer why would i ask question?? I already know answer i want a solution.

sneha73: f9

sneha73: let 3 no be xyz and their sum .. x+y+z=98 x/y=2/3 y/z=5/8 from this we will get __ x=2a y=3a y=5b z=8b ....so for 'y' we have 2 value 3a and 5b ..... soo 3a =5b so what we must multiply to get both value same ..... ----- in place of 'a' and b we take 10 and 6 ... when we multiply this number in respective places will get same value for y..that is 30

scorp9ocean: Thank You

sneha73: Its ok

Answered by Anonymous

Answer:

Step-by-step explanation:

Solution:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer: (c)

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