The sum of three numbers is 98 if the ratio of the first to second is 2:3
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sum of three numbers is 98
ratio = 2:3
= 2x & 3x
let the third side be x
2x + 3x + x = 98
6x = 98
x = 98/6
x =16.3 = third side
first side = 2x = 2×16.3 = 32.6
second side = 3x = 3×16.3 = 48.9
ratio = 2:3
= 2x & 3x
let the third side be x
2x + 3x + x = 98
6x = 98
x = 98/6
x =16.3 = third side
first side = 2x = 2×16.3 = 32.6
second side = 3x = 3×16.3 = 48.9
Answered by
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Answer:
Step-by-step explanation:
Let the three numbers be x, y and z.
Sum of the numbers is 98.
x + y + z = 98………………(i)
The ratio of the first to the second is 2/3.
x/y = 2/3.
x = 2/3 × y.
x = 2y/3.
The ratio of the second to the third is 5/8.
y/z = 5/8.
z/y = 8/5.
z = 8/5 × y.
z = 8y/5.
Put the value of x = 2y/3 and z = 8y/5 in (i).
2y/3 + y + 8y/5 = 98
49y/15 = 98.
49y = 98 × 15.
49y = 1470.
y = 1470/49.
y = 30 .
Therefore, the second number is 30.
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