Question

The sum of three numbers is 98. The ratio of the first to the second is 2/3, and the ratio of the second to the third is 5/8. The second number is:

Answer 1

Answer:

Step-by-step explanation:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer 2

Given :--- sum of three numbers = 98 , and ratio of first and second is 2:3 and second to third = 5:8

Let the number be A, B and C ,

A/q,

A:B = 2:3

B:C = 5:8

so,

A:B:C = (2×5):(5×3):(3×8) = 10:15:24

so, now let A, B and C be = 10x , 15x and 24x

A/q,

their sum is 98,

so,

10x+15x+24x = 98

49x = 98

x = 2

so,

second number B is = 15x = 15 × 2 = $\huge\blue{</strong><strong>3</strong><strong>0</strong><strong>}$