The sum of three numbers is 98. The ratio of
the first to the second is 2/3, and the ratio of the
second to the third is 5/8. The second number is:
Answers
Step-by-step explanation:
Let the three numbers be x, y and z.
Sum of the numbers is 98.
x + y + z = 98………………(i)
The ratio of the first to the second is 2/3.
x/y = 2/3.
x = 2/3 × y.
x = 2y/3.
The ratio of the second to the third is 5/8.
y/z = 5/8.
z/y = 8/5.
z = 8/5 × y.
z = 8y/5.
Put the value of x = 2y/3 and z = 8y/5 in (i).
2y/3 + y + 8y/5 = 98
49y/15 = 98.
49y = 98 × 15.
49y = 1470.
y = 1470/49.
y = 30 .
Therefore, the second number is 30.
Answer:
Ans is simple...
Step-by-step explanation:
Let the numbers be x,y, and z
SUM OF THE NUMBERS:
x+y+z=98 .. (1)
RATIO OF FIRST TO SECOND=2:3
therefore,
x/y=2/3
3x/2=y ... (2)( Substitute only y here)
RATIO OF SECOND TO THIRD=5:8
therefore,
y/z=5/8
y =5z/8
but we know by (2),
3x/2=5z/8
therefore substituting z alone we get,
12x/5=z .....(3)
SUBSTITUTE (1)AND(2) IN (1) ,
x+3x/2+12x/5=98
Multiply throughout by 10,
10x+15x+24x=980
49x=980
x=20
Substitute the value of x in (2),
3×20/2=y
y=30
Similarly Substitute both values of x and y in (1)
we get,
50 + z= 98
z= 48
THE THREE NUMBERS ARE 20 ,30 AND 48 RESPECTIVELY
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