Question

The sum of three numbers is 98. The ratio of the first to the second is 2/3, and the ratio of the second to the third is 5/8. The second number is:

Answer 1

❤️_______$<b>Hey Mate$________❤️

✌️_______UR ANSWER_______✌️

$<u>Solution$

Let the three numbers be x, y and z.

sum of the numbers is 98.

x + y + z = 98..................... (i)

The ratio of the first to the second is 2/3.
x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer...... 30


⤴️_____HOPE HELP YOU_____⤴️

Answer 2

Holla ^_^

☸ Required Answer is :

☮ Let the numbers are a, b nd c

Given, a+b+c = 98........eq. no. 1

Ratio of a nd b is 2/3
A.T.Q

➡ a/b = 2/3

➡ a = 2b/3

Ratio of b nd c is 5/8
A.T.Q

➡ b/c = 5/8

➡ c/b = 8/5

➡ c = 8b/5

Now putting the above values in eq. 1 ,

➡ 2b/3 + b + 8b/5 = 98

after Solving by taking lcm we get,

➡ 49b/15 = 98

➡ 49b = 1470

➡ b = 1470/49

➡ b = 30 .

Hence ,the second no. is 30.


Vielen Dank ♥