Question

The sum of three numbers is 980 if the ratio between first and second number is 324 and that of second and third is 327 find the difference between first and last number

Answer 1

Your Answer is 249 mmmmmm

Answer 2

380 is the difference between first and last number.

Given:

Sum of three numbers = 980

Ratio of first two numbers = 3:4

Ratio of second and third = 3:7

To find:

Difference between first and last number?

Solution:

Let the first number be x, second number be y, third number be z.

Then $x+y+z=98---(1)$

Also,  

$\frac{x}{y}=\frac{3}{4}---(2)$

$\Rightarrow y=\frac{4 x}{3}$

Also, $\frac{y}{z}=\frac{3}{7}----(3)$

Multiplying 2 and 3,  

$\begin{array}{l}{\frac{x}{y} \times \frac{y}{z}=\frac{3}{4} \times \frac{3}{7}} \\ {\frac{x}{z}=\frac{9}{28}}\end{array}$

$\Rightarrow z=\frac{28 x}{9}$

Substituting y and z in 1 gives

$\begin{array}{l}{x+\frac{4 x}{3}+\frac{28 x}{9}=980} \\ {\frac{9 x+12 x+28 x}{9}=980} \\ {49 x=980 \times 9=8820} \\ {x=\frac{8820}{49}=180}\end{array}$

$z=\frac{28 x}{9}=28 \times \frac{180}{9}=560$

Therefore, the Difference between first and last number is $\bold{z-x=560-180=380.}$