The sum of three numbers is an ap is 12 and their product is 48 find those numbers
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Step-by-step explanation:
let the three numbers be :
a+d , a , a-d
given the sum is 12 so add the numbers
3a = 12
a = 4 ( therefore the first number of the ap is 4)
(a+d)(a)(a-d) = 48 ( we take a to the left hand side it becomes division)
(a2 - d2) = 48/4
(42 - d2) = 12
16 - d2 = 12
-d2 = -4
d= 2
therefore the numbers are 2,4,6.
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Answered by
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Answer:
2, 4 and 6
Hope it helps u
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