Question

The sum of three numbers is AP is 12 and there product is 48. Find those numbers

Answer 1

Step-by-step explanation:

let, the three numbers are a-d, a, a+d

given, 3a=12=>a=3

a(a^2-d^2)=48

3(9-d^2)=48=>9-d^2=16=>d=+/-√7i

therefore, the three numbers are 3-√7i,3,3+√7i