Question

The sum of three numbers is eighty-one.the second number is twice the first number and the third number is six more than the second number. find the number

Answer 1

Answer:

The numbers are 15, 30 and 36.

Step-by-step explanation:

The sum of three numbers = 81

To Find :

the numbers

Solution :

First no. = x

Second no. = 2x

Third no. = 2x + 6

Total = 81

⇒ x + 2x + (2x + 6) = 81

⇒ x + 4x + 6 = 81

⇒ 5x = 81 - 6

⇒ 5x = 75

⇒ x = 75 / 5

⇒ x = 15

★ First no. = 15

★ Second no. :-

2(15) = 30

★ Third no. :-

2x + 6 = 2(15) + 6 = 36

Answer 2

✯✯ QUESTION ✯✯

The sum of three numbers is eighty-one.the second number is twice the first number and the third number is six more than the second number. find the number.

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✰✰ ANSWER ✰✰

$\implies\tt{Let\:the\:first\:no.\:be=y}$

➮As Second number is twice of 1st no.So ,

$\implies\tt{Second\:no.\:be=2y}$

➮Now , third number is six more than second number.So ,

$\implies\tt{Third\:no.\:be=2y+6}$

$\implies\tt{Sum\:of\:Numbers=81}$

➥A.T.Q : -

$\implies\tt{y+2y+2y+6=81}$

$\implies\tt{5y+6=81}$

$\implies\tt{5y=81-6}$

$\implies\tt{5y=75}$

$\implies\tt{y=\cancel\dfrac{75}{5}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{y}\orange{=}\purple{15}}}$

➥Now ,

$\implies\tt{1st\:No.=15}$

$\implies\tt{2nd\:No.=2(15)}$

$\implies\tt\bold{30}$

$\implies\tt{3rd\:No.=2(15)+6}$

$\implies\tt{30+6}$

$\implies\tt\bold{36}$

_______________________

✔VERIFICATION : -

$\implies\tt{13+26+32=81}$

$\implies\tt{81=81}$

$\orange\longmapsto\:\large\underline{\boxed{\bf\pink{L.H.S}\red{=}\green{R.H.S}}}$

✺ HENCE VERIFIED ✺