Question

The sum of three numbers of an ap is 3 and the product of the first and the third number is my verified 13 numbers

Answer 1

I have a good idea to solve the problem in few minutes

Answer 2

The numbers in an A.P are -5,1,6 or 6,1,-5.

Step-by-step explanation:

Given : The sum of 3 numbers of an ap is 3 and the product of the first and the third number is minus 35.

To find : The three number ?

Solution :

Let the three numbers of an A.P is (a-d),a,(a+d).

The sum of 3 numbers of an AP is 3.

i.e. $a-d+a+a+d=3$

$3a=3$

$a=\frac{3}{3}$

$a=1$

The product of the first and the third number is minus 35.

i.e. $(a-d)(a+d)=-35$

$a^2-d^2=-35$

$(1)^2-d^2=-35$

$d^2=36$

$d=\sqrt{36}$

$d=\pm 6$

When a=1 and d=6,

a-d=1-6=-5

a+d=1+6=7

The numbers are -5,1,6.

When a=1 and d=-6,

a-d=1-(-6)=7

a+d=1+(-6)=-5

The numbers are 6,1,-5.

#Learn more

The sum of 3 numbers in ap is 12 and the sum their cubes is 288 . find the numbers

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