Question

The sum of three numbers of AP is -3
their product find the numbers,
is 8. find the numbers ​

Answer 1

Answer:

By Distance Formula :- d=√((x_2-x_1)²+(y_2-y_1)²)

$\sf d(AB) = \bf{\sqrt{(1 - 1)^2 + (6 - 2)^2}}\</p><p></p><p></p><p></p><p></p><p></p><p></p><p>[tex]\sf d(BC) = \bf{\sqrt{(1 + 2√3 - 1)^2 + (4 - 6)^2}}</p><p>$

\: \: \: \: \: \: \: \: \: \: \: \: \: \:\sf = \bf{\sqrt{( 2√3 )^2 + ( - 2)^2}}

[/tex]

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = \bf{\sqrt{4(3) + (4 )}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = \bf{\sqrt{12 + 4}}</p><p>$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = \bf{\sqrt{16}}</p><p>$

$\sf d(AC) = \bf{\sqrt{(1 + 2√3 - 1)^2 + (4 - 2)^2}}</p><p>$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = \bf{\sqrt{( 2√3 )^2 + ( 2)^2}}</p><p>$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = \bf{\sqrt{( 4(3 ) + 4}}</p><p>$

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \ = \{\sqrt{12 + 4}}

[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = \bf{\sqrt{16}}

Distance AB = BC = AC = 4 ..From 1,2,3

Therefore △ABC is equaliteral triangle