Question

the sum of three numbers of gp is 57 and product is 343

Answer 1

Let the numbers be a, ar, ar²
Now, sum of the numbers : a+ar+ar² = 57 ----------- (i)
" product of numbers : a*ar*ar² = 343 -----------(ii)
a³r³ = 343
(ar)³ = 343
on comparing, we get
ar = 7 ⇒ a = 7/r
putting the value of ar in eq. (i)
7/r + 7 + 7r = 57
7r² - 50r - 7 = 0
7r² -49r - r - 7 = 0
7r (r-7) +1 (r-7) = 0
∴ r = 7 & a = 1
Hence, numbers are 1, 7, 49 Ans

Answer 2

Answer:

refer to the attachment for the solution..