The sum of three numbers,whose ratios are 10/3 :21/5 :43/8 is 4917. Find the numbers.
Answers
Step-by-step explanation:
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Given : sum of three numbers,whose ratios are 10/3 :21/5 :43/8 is 4917
To find : Numbers
Solution:
Ratios are
10/3 : 21/5 : 43/8
Multiplying by 120 Each ratio
=> 400 : 504 : 645
Let say three numbers are
400k , 504k & 645k
400k + 504k + 645k = 4917
=> 1549k = 4917
=> k = 4917/1549
400k = 400 * 4917/1549 = 19,66,800/1549
504k = 504 * 4917/1549 = 24,78,168/1549
645k =645 * 4917/1549 = 31,71,465/1549
Ratios are
10/3 : 21/5 : 49/8
Multiplying by 120 Each ratio
=> 400 : 504 : 735
Let say three numbers are
400k , 504k & 735k
400k + 504k + 735k = 4917
=> 1639k = 4917
=> k = 3
400k = 400 *3 = 1200
504k = 504 * 3 = 1512
735k =735 * 3 = 2205
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