Math, asked by ayushiahuja3275, 10 months ago

The sum of three numbers,whose ratios are 10/3 :21/5 :43/8 is 4917. Find the numbers.

Answers

Answered by imraushanraaz
1

Step-by-step explanation:

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Answered by amitnrw
2

Given :  sum of three numbers,whose ratios are 10/3 :21/5 :43/8 is 4917

To find : Numbers

Solution:

Ratios are

10/3  : 21/5  : 43/8

Multiplying by 120  Each ratio

=> 400 : 504 : 645

Let say three numbers are

400k  , 504k  & 645k

400k + 504k + 645k  = 4917

=> 1549k  = 4917

=> k = 4917/1549

400k  = 400 * 4917/1549  =  19,66,800/1549

504k = 504 *  4917/1549 =  24,78,168/1549

645k =645 *  4917/1549 =    31,71,465/1549

Ratios are

10/3  : 21/5  : 49/8

Multiplying by 120  Each ratio

=> 400 : 504 : 735

Let say three numbers are

400k  , 504k  & 735k

400k + 504k + 735k  = 4917

=> 1639k  = 4917

=> k = 3

400k  = 400 *3  =  1200

504k = 504 *  3 =  1512

735k =735 *  3 =    2205

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