Question

The sum of three numbers , whose ratios are 10/3:21/5:49/8 is 4917 . Find the number

Answer 1

Answer:

The numbers

are 1200,1512 and 2205.

Explanation:

the three numbers are represented in the form of ratio

10/3: 21/5: 49/8

the simplified form of these fractions into a ratio:

multiply each term by 5,3 and 8.

we get,

10*5*3*8/3 :21*3*5*8/5:  49*3*8*5/8

400:504: 735

As we know,

we have the sum of numbers as 4917.

now 400x+504x+735x= 4917

1639x=4917

x=3

hence the numbers are, 400x,504x,735x

as 1200,1512 and 2205.

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Answer 2

Answer:

The figures are 1200, 1512, and 2205.

Explanation:

Given:

The ratio $\frac{10}{3}$: $\frac{21}{5}$: $\frac{49}{8}$ is used to represent the three integers.

An integer, pronounced "IN-tuh-jer," is a whole number that can be positive, negative, or zero and is not a fraction. Integer examples include: -5, 1, 5, 8, 97, and 3,043. 1.43, 1 3/4, and 3.14 are examples of numbers that are not integers.

Solution:

Multiply each term by 5, 3, and 8 to convert these fractions into a ratio in their simplest form.

we get, 10×5×3×$\frac{8}{3}$:21×3×5×$\frac{8}{5}$: 49×3×8×$\frac{5}{8}$

400:504: 735

As far as we are aware, the total of our numbers is 4917.

at this point, 400x+504x+735x= 4917 1639x= 4917 x= 3

As a result, the numbers 400x, 504x, and 735x equal 1200, 1512, and 2205.

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