the sum of three numbers, whose ratios are 3 1/3 : 4 1/5 : 6 1/8, is 4917. find the numbers.
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10/3x+21/5x+49/8x=4917.......(1)
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
=4917*3*8*5
x[400+504+735]=590040
x[1639]=590040
x=590040/1639=360
therefore, x=360
put the value of x into equation (1) and we get,
10/3x=1200
21/5x=1512
49/8x=2205.
the numbers are 1200,1512 and 2205.
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
=4917*3*8*5
x[400+504+735]=590040
x[1639]=590040
x=590040/1639=360
therefore, x=360
put the value of x into equation (1) and we get,
10/3x=1200
21/5x=1512
49/8x=2205.
the numbers are 1200,1512 and 2205.
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