Math, asked by bhaskarraj18, 1 year ago

The sum of three numbers, whose ratios are 3 1/3 : 4 1/5 : 6 1/8, is 4917. find the numbers.

Answers

Answered by vee1
86

10/3x+21/5x+49/8x=4917.........(1)
x[10/3+21/5+49/8]=4917
x[10*5*8+21*3*8+49*3*5]
= 4917*3*5*8
x[400+504+734]=4917*3*5*8
x[1639]=590040
x=590040/1639=360
x=360.
put the value of x into equation (1) and we get,
10/3x=1200,
21/5x=1512,
49/8x=2205.
we get the three numbers are 1200, 1512, and 2205.




Answered by ruhani745
32

Answer:

1200,1512,2205

Step-by-step explanation:

number=x

3 1/3x=10/3x , 4 1/5 x=21/5 x , 6 1/8x=49/8x

10 /3x+ 21/5x + 49/8x =4917

Lcm=120

400x+ 504x +735x/120=4917

400x+ 504x +735x=4917*120

1639x=590040

x=590040/1639

x=360

10/3x=1200

21/5x=1512

49/8x=2205

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