Question

the sum of three positive consecutive integers is 96 find the largest number​

Answer 1

Answer:

So the three consecutive numbers whose sum is 96 are 31, 32 and 33. Thus 33 is the largest of the three consecutive numbers which add up to 96.

Answer 2

Step-by-step explanation:

just working thru it: 2 have to be odd, if only 1 is 96 couldn’t happen; consecutive, 3 natural numbers [assumed] divide final result by 3; that is 32, so there is a higher and lower value

31 + 32 + 33 = 96

96/3 = 32

So the three consecutive numbers whose sum is 96 are 31, 32 and 33. Thus 33 is the largest of the three consecutive numbers which add up to 96.

OR

let three consecutive numbers are (x+1),(x+2)and (x+3).

so,(x+1)+(x+2)+(x+3)=96

>> 3x+6=96

>>x=30

(x+1)=30+1=31

(x+2)=30+2=32

(x+3)=30+3=33

so, the largest no. is 33.

hope it helps✌☺