Question

the sum of three positive consecutive nimbers is 48 find the smallest integer​

Answer 1

Answer:

this is the answer

Step-by-step explanation:

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Answer 2

Answer:

let the three consecutive numbers be:

x+x+x=48

3x=48

x=48/3

= 16

now the numbers are 16-1, 16, and 16+1

it's 15, 16 and 17

the smallest number is 15.