Question

the sum of three positive integers in AP is 24 and their product is 480 .find the numbers​

Answer 1

Answer:

Let the three terms be a-d,a,a+d

Sum=24 Product=480

.°.a-d+a+a+d=24(d d cut off)

3a=24

.°.a=8

(a-d)(a)(a+d)=480

(8-d)(8)(8+d)=480[.°.a=8]

(8-d)(8+d)=60

$64 - d {2} = 60$

$d {2} = \sqrt{4} = 2$

If a=8,d=2 the terms are

a-d=8-2=6,a=8,a+d=8+2=10

.°.The terms are 6,8,10.

We will get the same values if we'll consider d=-2

Step-by-step explanation:

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