the sum of three prime number 80 and the first two prime number difference is 4 .is there formula method for that
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Answer:
Step-by-step explanation:
The three prime numbers whose sum is 80
and difference of two of them is 4 are 41,37,2.
As you can see
41+ 37+2=78+2=80
41-37=4.
You must be thinking how i got this result.You have to choose two primes such that their difference is four.Such primes are (3,7),(7,11),(13,17),(19,23),(37,41),(43,47).
So, choose one of them and then find the other prime.
So, your result which satisfy the above condition are 41,37,2.
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